Question:medium

If the foci of the ellipse \[ \frac{x^2}{25}+\frac{y^2}{k^2}=1 \qquad (k^2<25) \] and the hyperbola \[ \frac{x^2}{k}-\frac{y^2}{5}=1 \] are the same, then the product of the lengths of the latus rectum of the ellipse and that of the hyperbola is:

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Remember the latus rectum formulas: For an ellipse: \[ L=\frac{2b^2}{a} \] For a hyperbola: \[ L=\frac{2b^2}{a} \] The formula is the same; only the values of \(a\) and \(b\) differ according to the conic.
Updated On: Jun 17, 2026
  • \(25\)
  • \(50\)
  • \(16\)
  • \(32\)
Show Solution

The Correct Option is D

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