Question:medium

If the enthalpy of vaporization of water is \(18.6\,\text{kJ mol}^{-1}\), the entropy of its vaporization will be:

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Entropy change = enthalpy change divided by absolute temperature.
Updated On: Mar 24, 2026
  • \(0.5\,\text{kJ K}^{-1}\text{mol}^{-1}\)
  • \(1.0\,\text{kJ K}^{-1}\text{mol}^{-1}\)
  • \(1.5\,\text{kJ K}^{-1}\text{mol}^{-1}\)
  • \(2.0\,\text{kJ K}^{-1}\text{mol}^{-1}\)
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The Correct Option is A

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