Question:medium
If the drift velocity of electrons in a copper wire of cross-sectional area $2\,mm^2$ carrying current $I$ is $v_1$ and that in another copper wire of cross-sectional area $1.5\,mm^2$ carrying current $2I$ is $v_2$, then the ratio $v_1 : v_2$ is
If the drift velocity of electrons in a copper wire of cross-sectional area $2\,mm^2$ carrying current $I$ is $v_1$ and that in another copper wire of cross-sectional area $1.5\,mm^2$ carrying current $2I$ is $v_2$, then the ratio $v_1 : v_2$ is
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Drift velocity inversely proportional to area.
Updated On: Apr 24, 2026
- $3:8$
- $2:4$
- $8:3$
- $4:2$
- $1:3$
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The Correct Option is A
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