Phase 1: Apply Charge Equation
The quantity of electric charge \( Q \) that traverses a conductor is determined by the equation: \[ Q = I \times t \] In this equation:
- \( I \) represents the electrical current,
- \( t \) denotes the duration for which the current is active.
Phase 2: Input Provided Data
The provided data includes:
- Current \( I = 2 \, \text{A} \),
- Time \( t = 10 \, \text{minutes} \), which converts to \( 10 \times 60 = 600 \, \text{seconds} \).
Substituting these values into the equation yields: \[ Q = 2 \times 600 = 1200 \, \text{C} \]
Conclusion:
Consequently, the cumulative electric charge passing through the conductor amounts to \( 1200 \, \text{C} \). This corresponds to choice (1).
A 5 $\Omega$ resistor and a 10 $\Omega$ resistor are connected in parallel. What is the equivalent resistance of the combination?