Question:medium

If the current passing through a coil of self-inductance \(50\) mH having \(50\) turns is \(5\) A, then the magnetic flux linked with the coil (in \(10^{-3}\) Wb) is

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Remember, \[ \boxed{ L=\frac{N\phi}{I}, } \] where \[ \boxed{N\phi} \] is the flux linkage. Read the question carefully to distinguish between magnetic flux \((\phi)\) and flux linkage \((N\phi)\).
Updated On: Jul 18, 2026
  • \(5\)
  • \(20\)
  • \(10\)
  • \(250\)
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The Correct Option is D

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