Step 1: Touching the x-axis condition.
A circle touches the x-axis when the distance from its centre to that axis equals its radius. For $x^2+y^2+2gx+2fy+c=0$ this becomes $g^2 = c$.
Step 2: Match coefficients.
From $x^2 + y^2 - 4x - 6y + \lambda = 0$: $2g = -4$ so $g = -2$, and $c = \lambda$.
Step 3: Apply the condition.
\[ g^2 = c \implies (-2)^2 = \lambda \]
Step 4: Compute.
\[ 4 = \lambda \]
Step 5: Quick check.
Centre is $(2,3)$, radius is $\sqrt{4 + 9 - 4} = 3$, which equals the $y$-coordinate of the centre, confirming it touches the x-axis.
Step 6: Conclusion.
\[ \boxed{ \lambda = 4 } \]