Question:medium
If the centre of the circle inscribed in a square formed by the lines $x^2 - 8x + 12 = 0$ and $y^2 - 14y + 45 = 0$ is $(a,b)$, then $a + b$ is
If the centre of the circle inscribed in a square formed by the lines $x^2 - 8x + 12 = 0$ and $y^2 - 14y + 45 = 0$ is $(a,b)$, then $a + b$ is
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When quadratic equations define boundaries, factor them to get straight lines and then find the midpoint to locate the center.
Updated On: Apr 30, 2026
- $11$
- $9$
- $7$
- $5$
- $4$
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The Correct Option is B
Solution and Explanation
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