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If the angle between the planes ax-y+3z=2a and 3x+ay+z=3a is \( \frac{\pi}{3} \) then the direction ratios of the line perpendicular to the plane (a+2)x+(a-4)y+2az=a are
If the angle between the planes ax-y+3z=2a and 3x+ay+z=3a is \( \frac{\pi}{3} \) then the direction ratios of the line perpendicular to the plane (a+2)x+(a-4)y+2az=a are
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The direction ratios of a line perpendicular to a plane \(Ax+By+Cz+D=0\) are simply the coefficients of x, y, and z, which are (A, B, C). These are the components of the normal vector to the plane.
Updated On: Mar 30, 2026
- (2,-1,2)
- (2,1,-2)
- (2,1,2)
- (2,2,-1)
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The Correct Option is A
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