Question

If the air is contained in a tyre at 2.0 atm gauge pressure, then absolute pressure of air will be

• A. \(1.013 \times 10^5 \text{ Pa}\)
• B. \(2.026 \times 10^5 \text{ Pa}\)
• C. \(3.04 \times 10^5 \text{ Pa}\)
• D. \(4.052 \times 10^5 \text{ Pa}\)

Hint:

To simplify calculations, add the pressures in atmospheric units (\(\text{atm}\)) first before converting to Pascals:
\[ P_{\text{abs}} = 2.0 \text{ atm (gauge)} + 1.0 \text{ atm (atmosphere)} = 3.0 \text{ atm (absolute)} \] Then: \(3.0 \times 1.013 \times 10^5 \text{ Pa} = 3.039 \times 10^5 \text{ Pa}\). This minimizes arithmetic errors.

Answer 1

The Correct Option is C