Question:medium

If the 9546 \(\AA\) wavelength spectral line in hydrogen spectrum is due to the transition of an electron from a higher orbit to \(n^{th}\) lower orbit, then the value of \(n\) is:

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Series of hydrogen spectrum: \[ n=1 \rightarrow \text{Lyman} \] \[ n=2 \rightarrow \text{Balmer} \] \[ n=3 \rightarrow \text{Paschen} \] \[ n=4 \rightarrow \text{Brackett} \]
Updated On: Jun 18, 2026
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The Correct Option is C

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