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If \[ \tan^{-1}\left(\frac{1}{2\sqrt2}\right) - \cos^{-1}\left(\frac{1}{\sqrt3}\right) + \sin^{-1}(x) = 0, \] then $x=$

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For inverse trigonometric equations, assign angles to the inverse functions and determine their sine, cosine, or tangent values using right triangles. Then apply standard trigonometric identities.

Updated On: Jul 29, 2026

$\dfrac{1}{\sqrt3}$
$\dfrac{2}{3\sqrt3}$
$\dfrac{1}{2\sqrt3}$
$\dfrac{\sqrt2}{\sqrt3}$

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The Correct Option is A

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If \[ \tan^{-1}\left(\frac{1}{2\sqrt2}\right) - \cos^{-1}\left(\frac{1}{\sqrt3}\right) + \sin^{-1}(x) = 0, \] then \(x=\)

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The Correct Option is A

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