Question:medium

If $\phi = 2x^{3}y^{2}z^{4}$ then $\nabla^{2}\phi = $

Show Hint

$\nabla^2$ is simply the sum of the second partial derivatives of the scalar field.
  • $12xy^{2}z^{4} + 4x^{2}z^{4} + 20x^{3}y^{2}z^{3}$
  • $12xy^{2}z^{4} + 4x^{3}z^{4} + 24x^{3}y^{2}z^{2}$
  • $2x^{2}y^{2}z + 4x^{3}z^{4} + 24x^{3}y^{2}z^{2}$
  • $4xy^{2}z + 4x^{2}z^{4} + 24x^{3}y^{2}z^{2}$
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0

Top Questions on Vector Calculus