The question pertains to the electric field present across a p-n junction when no external voltage is applied. Understanding the concept of a p-n junction in semiconductor physics is crucial to solving this question.
A p-n junction is formed by joining p-type and n-type semiconductors. On formation, electrons from the n-type side diffuse across the junction into the p-type side, where they recombine with holes. Similarly, holes from the p-type region diffuse into the n-type region. This process creates a region devoid of mobile charge carriers, known as the depletion region, at the interface. The diffusion of charge carriers across the junction leads to the formation of an internal electric field.
This built-in electric field is directed from the n-type to the p-type side, acting as a barrier that opposes further diffusion of charge carriers. It is this electric field that maintains equilibrium within the p-n junction when no external voltage is applied.
Let's examine the options one by one to corroborate our understanding:
Therefore, the correct answer is: an electric field pointing from n-type to p-type side across the junction.