Question:medium

If $\log_3 2$, $\log_3 (2^x - 5)$ and $\log_3 \left(2^x - \frac{7}{2}\right)$ are in AP, the value of $x$ is

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In AP: $2b = a + c$. Also, argument of log must be positive.

Updated On: Apr 8, 2026

$2$
$3$
$0$
$\frac{1}{3}$

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The Correct Option is B

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If $\log_3 2$, $\log_3 (2^x - 5)$ and $\log_3 \left(2^x - \frac{7}{2}\right)$ are in AP, the value of $x$ is

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The Correct Option is B

Solution and Explanation

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