Question:medium

If \(iz^4 + 1 = 0\) then \(z\) can take the value

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For \(z^n = r(\cos\theta + i\sin\theta)\), roots are \(\cos\frac{\theta+2k\pi}{n}\).
Updated On: Apr 23, 2026
  • \(\cos \frac{\pi}{8} + i\sin \frac{\pi}{8}\)
  • \(\cos \frac{\pi}{4} + i\sin \frac{\pi}{4}\)
  • \(\cos \frac{3\pi}{8} + i\sin \frac{3\pi}{8}\)
  • \(\cos \frac{\pi}{2} + i\sin \frac{\pi}{2}\)
Show Solution

The Correct Option is B

Solution and Explanation

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