Step 1: Understand what is being asked.
We are given $\frac{AB}{EF}=\frac{BC}{DE}=\frac{CA}{DF}$ for triangles $ABC$ and $DEF$, and we need the correct similarity statement. Instead of testing each option one by one, let us read off the vertex correspondence directly from the given ratios.
Step 2: Match vertices using the first two ratios.
Look at the equal ratios $\frac{AB}{EF}=\frac{BC}{DE}$. The letter common to both numerators (sides of triangle $ABC$) is $B$. The letter common to both denominators (sides of triangle $DEF$) is $E$.
Since in similar triangles matching sides come from matching vertices, this tells us:
\[ B \leftrightarrow E \]
Step 3: Match vertices using the next pair of ratios.
Now look at $\frac{BC}{DE}=\frac{CA}{DF}$. The letter common to both numerators is $C$, and the letter common to both denominators is $D$. This gives:
\[ C \leftrightarrow D \]
Step 4: Find the last correspondence and write the similarity.
The only vertex of triangle $ABC$ left unmatched is $A$, and the only vertex of triangle $DEF$ left unmatched is $F$, so:
\[ A \leftrightarrow F \]
Putting all three correspondences together, $A\to F$, $B\to E$, $C\to D$, we can write $\Delta ABC \sim \Delta FED$. Reading the vertices of $DEF$ in the order that matches $ABC$ reversed gives the equivalent, more natural statement:
\[ \Delta DEF \sim \Delta CBA \]
Final Answer:
The correct similarity is $\Delta DEF \sim \Delta CBA$, matching option (B).
\[ \boxed{\Delta DEF \sim \Delta CBA} \]