Question:medium

If geometric mean and harmonic mean of two numbers are \(16\) and \(\frac{64}{5}\) respectively, then \(a:b\) is:

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Use \(GM^2 = ab\) and \(HM = \frac{2ab}{a+b}\) to solve for \(a\) and \(b\).
Updated On: Apr 16, 2026
  • \(4:1\)
  • \(3:2\)
  • \(2:3\)
  • \(1:4\)
Show Solution

The Correct Option is A

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