Question:medium

If $\frac{x^2+1}{(x^2+2)(x^2+3)} = \frac{Ax+B}{x^2+2} + \frac{Cx+D}{x^2+3}$, then $A+B+C+D=$

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For partial fractions involving only even powers of $x$ (like $x^2, x^4$), a quick method is to substitute $y=x^2$ and solve the simpler decomposition in terms of $y$. Then substitute back to find the coefficients.

Updated On: Mar 30, 2026

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1
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6

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The Correct Option is B

Solution and Explanation

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If $\frac{x^2+1}{(x^2+2)(x^2+3)} = \frac{Ax+B}{x^2+2} + \frac{Cx+D}{x^2+3}$, then $A+B+C+D=$

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The Correct Option is B

Solution and Explanation

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