Question

If \[ \frac{(x+1)^2}{x^3+x} = \frac{A}{x} + \frac{Bx+C}{x^2+1}, \] then \[ \sin^{-1}\!\left(\frac{A}{C}\right)=\_ \] 

• A. $\pi/6$
• B. $\pi/4$
• C. $\pi/3$
• D. $\pi/2$

Hint:

$sin^{-1}(1)$ is always $90^{\circ}$ or $\pi/2$.

Answer 1

The Correct Option is D