Question:medium

If \[ \frac{dy}{dx} = y \] then which of the following is the correct solution?

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Any process where the growth rate of a quantity is proportional to its size yields an exponential function.
Thus, the equation \( \frac{dy}{dx} = ky \) always has the standard solution \( y = Ce^{kx} \).
Remembering this standard model saves valuable time during competitive exams.
Updated On: Jun 3, 2026
  • \( y = Ce^x \)
  • \( y = Cx \)
  • \( y = x^2 + C \)
  • \( y = \log x \)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
This question represents a first-order ordinary differential equation. A differential equation establishes a structural relationship between an unknown mathematical function $y$ and its derivatives. To solve equations where variables can be isolated on opposing sides of the equality symbol, we employ the method of separation of variables.
Step 2: Key Formula or Approach:
The given differential equation is: $$ \frac{dy}{dx} = y $$ We isolate all terms containing the dependent variable $y$ along with its differential element $dy$ on the left side, and position the independent variable differential element $dx$ on the right side. Once separated, we perform integration on both sides simultaneously: $$ \int \frac{1}{y} \, dy = \int 1 \, dx $$ The standard integration formula for the reciprocal function is $\int \frac{1}{y} \, dy = \ln|y| + C$.
Step 3: Detailed Explanation:
Let's carry out the separation of variables and subsequent integration actions systematically: 1. Separate the variables: Divide both sides by $y$ and multiply both sides by $dx$: $$ \frac{1}{y} \, dy = dx $$ 2. Integrate both sides: $$ \int \frac{1}{y} \, dy = \int dx $$ $$ \ln|y| = x + C_1 $$ Where $C_1$ represents the initial arbitrary constant of integration. 3. Solve for $y$ explicitly: Convert the logarithmic expression into its equivalent exponential base form: $$ |y| = e^{x + C_1} $$ Using the algebraic laws of exponents, we can unpack the right-side addition into a product: $$ |y| = e^{x} \cdot e^{C_1} $$ 4. Simplify the constant term: Since $C_1$ is an arbitrary constant, the term $e^{C_1}$ (or $\pm e^{C_1}$ when removing the absolute value bars) is also just another constant. We can redefine this entire constant factor as $C$: $$ y = Ce^x $$ This explicit solution corresponds perfectly with option (A).
Step 4: Final Answer:
The correct solution to the differential equation is $y = Ce^x$.
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