Question:medium

The order and degree of the differential equation: \[ \left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^3 = \frac{d^2y}{dx^2}, \] respectively, are:

Show Hint

The order of a differential equation is determined by the highest derivative present, while the degree is determined by the power of the highest order derivative after eliminating radicals and fractions involving derivatives.
Updated On: Feb 25, 2026
  • 1, 2
  • 2, 3
  • 2, 1
  • 2, 6
Show Solution

The Correct Option is C

Solution and Explanation

To ascertain the order and degree of the provided differential equation, execute the following steps:1. Order: The order is defined by the highest-order derivative present. In this instance, the highest-order derivative is \( \frac{d^2y}{dx^2} \). Consequently, the order of the equation is \( 2 \).2. Degree: The degree is determined by the exponent of the highest-order derivative, assuming the equation is free of fractional powers and radicals concerning derivatives. The given equation is \( \left[ 1 + \left( \frac{dy}{dx} \right)^2 \right]^3 = \frac{d^2y}{dx^2} \). The highest-order derivative, \( \frac{d^2y}{dx^2} \), is raised to the power of \( 1 \). Therefore, the degree of the equation is \( 1 \).In conclusion, the order and degree of the differential equation are \( 2 \) and \( 1 \), respectively. Final Answer: (C) 2, 1.
Was this answer helpful?
0