Question:medium

If \( \frac{a}{b} = \frac{1}{3} \) and \( \frac{b}{c} = \frac{3}{4} \), then the value of \( \frac{a+2b}{b+2c} \) is:

Show Hint

Convert ratios into variables for quick simplification.
Updated On: Apr 17, 2026
  • \( \frac{28}{33} \)
  • \( \frac{7}{11} \)
  • \( \frac{1}{2} \)
  • None of these
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This is a problem of ratios and proportions. We should express all variables (\(a, b, c\)) in terms of a single variable to simplify the target expression.
Step 2: Detailed Explanation:
Given:
\[ \frac{a}{b} = \frac{1}{3} \implies b = 3a \]
\[ \frac{b}{c} = \frac{3}{4} \implies c = \frac{4b}{3} \]
Substitute \(b = 3a\) into the equation for \(c\):
\[ c = \frac{4(3a)}{3} = 4a \]
Now, substitute \(b = 3a\) and \(c = 4a\) into the target expression:
\[ \frac{a + 2b}{b + 2c} = \frac{a + 2(3a)}{3a + 2(4a)} \]
\[ = \frac{a + 6a}{3a + 8a} = \frac{7a}{11a} = \frac{7}{11} \]
Step 3: Final Answer:
The value is \(7/11\).
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