Question:medium

If $\frac{42-19x}{(x^{2}+1)(x-4)}=\frac{Ax+B}{x^{2}+1}+\frac{C}{x-4}$ then $B =$

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To find constants in partial fractions, substitute values of $x$ that make terms zero or compare coefficients of like powers.

Updated On: Jul 4, 2026

-11
11
-2
2

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The Correct Option is D

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