Question

If $\frac{2^{\frac{1}{3}} + 27a^{\frac{5}{3}}}{(\frac{a}{3})^{-\frac{1}{3}} + 3a^{\frac{2}{3}}} = 2 - ka^{\frac{1}{3}} + 9a^{\frac{2}{3}}$, then $k = $?

• A. $\sqrt{2}$
• B. $\sqrt{6}$
• C. $3\sqrt{2}$
• D. $3\sqrt{6}$

Hint:

Use the identity $a^3+b^3 = (a+b)(a^2-ab+b^2)$ to simplify.

Answer 1

The Correct Option is D