Question:medium
If \( f(x) = \sin^{-1} \left( \frac{1 - \cos 2x}{2 \sin x} \right) \), then \( |f'(x)| \) is equal to
If \( f(x) = \sin^{-1} \left( \frac{1 - \cos 2x}{2 \sin x} \right) \), then \( |f'(x)| \) is equal to
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Always simplify trigonometric expressions before differentiating inverse functions.
Updated On: May 8, 2026
- \( |\sin x| \)
- \( x \)
- \( 0 \)
- \( |\cos x| \)
- \( 1 \)
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The Correct Option is
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