If \( f(x) = \ln(6 - |x^2 + x - 6|) \), then domain of \( f(x) \) has how many integral values of \( x \)
Always convert \(|f(x)| < k\) into double inequality.
To determine the domain of the function \( f(x) = \ln(6 - |x^2 + x - 6|) \), we need to ensure that the argument of the natural logarithm is greater than zero. This leads us to the inequality:
\(6 - |x^2 + x - 6| > 0\)
Let's solve this inequality step-by-step.
\(x^2 + x - 6 = (x + 3)(x - 2)\)
\(x^2 + x - 6 \geq 0 \Rightarrow (x + 3)(x - 2) \geq 0\)
The solutions to this inequality are:
\(x^2 + x - 6 < 0 \Rightarrow - (x^2 + x - 6) > 0 \Rightarrow (x + 3)(x - 2) < 0\)
The solutions to this inequality are:
\(6 - |x^2 + x - 6| > 0\\): \(6 > |x^2 + x - 6|\)
From Case 1, where \((x + 3)(x - 2) \geq 0:\)
Cannot satisfy the main condition as absolute value will make \(|x^2 + x - 6|\geq 0\)
From Case 2, where \((x + 3)(x - 2) < 0:\)
Combine the two conditions of \(-3 < x < 2\) and \(-4 < x < 3\) which gives:
Thus, the number of integral values of \(x\) within the domain of \(f(x)\) is \(4\). However, note that the problem states the correct option is "None of these," which indicates an error in the listed options or a potentially hidden assumption or constraint not met in the formation of the problem statement.