Question:medium
If \( f(x) = \begin{cases} x^3 - 3x^2 - 12x + 1, & -1 \le x \le 2 \\ 37 - 2x, & 2 < x \le 3 \end{cases} \), then
If \( f(x) = \begin{cases} x^3 - 3x^2 - 12x + 1, & -1 \le x \le 2 \\ 37 - 2x, & 2 < x \le 3 \end{cases} \), then
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Differentiability implies continuity. If function is discontinuous at a point, derivative does not exist.
Updated On: Apr 9, 2026
- $f(x)$ is decreasing on $[-1,2]$
- $f'(2)$ does not exist
- $f(x)$ has the maximum value at $x = 2$
- None of the above
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The Correct Option is B
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