If $f^{\prime}(5)=\frac{3}{5}$ then the value of $\lim_{h\rightarrow 0}\frac{f(5+10h)-f(5)}{h}$ is equal to
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Logic Tip: A very useful shortcut for limits resembling the derivative definition is: $\lim_{h \to 0} \frac{f(x+ah)-f(x)}{h} = a \cdot f'(x)$. Here, $a=10$, so the answer is immediately $10 \cdot f'(5) = 10(3/5) = 6$.