Question

If electromagnetic waves of power 600 W incident on a non-reflecting surface, then the total force acting on the surface is

• A. $12 \times 10^{-6}$ N
• B. $9 \times 10^{-9}$ N
• C. $6 \times 10^{-6}$ N
• D. $2 \times 10^{-6}$ N

Hint:

For total absorption: $F = P/c$. For total reflection: $F = 2P/c$.

Answer 1

The Correct Option is D