To find the value of \(n\) such that \(C(n,2) : C(n,3) = \frac{44}{3}\), we need to use the concept of combinations.
The formula for combinations is:
\(C(n, r) = \frac{n!}{r!(n-r)!}\)
First, calculate \(C(n,2)\):
\(C(n,2) = \frac{n(n-1)}{2}\)
Now, calculate \(C(n,3)\):
\(C(n,3) = \frac{n(n-1)(n-2)}{6}\)
\(3n - 6 = 44\)
\(3n = 50\)
\(n = 6\)
Hence, the correct value of \(n\) is 6.
Correct Answer: \(6\)