Question:medium

If $C(n,2) : C(n,3) = 2 : 44 : 3$, then n is equal to

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$C(n,r) = \frac{n!}{r!(n-r)!}$.
Updated On: Apr 30, 2026
  • $6$
  • $7$
  • $5$
  • $8$
Show Solution

The Correct Option is A

Solution and Explanation

To find the value of \(n\) such that \(C(n,2) : C(n,3) = \frac{44}{3}\), we need to use the concept of combinations.

The formula for combinations is:

\(C(n, r) = \frac{n!}{r!(n-r)!}\)

First, calculate \(C(n,2)\):

\(C(n,2) = \frac{n(n-1)}{2}\)

Now, calculate \(C(n,3)\):

\(C(n,3) = \frac{n(n-1)(n-2)}{6}\)

\(3n - 6 = 44\)

\(3n = 50\)

\(n = 6\)

Hence, the correct value of \(n\) is 6.

Correct Answer: \(6\)

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