Question:medium

If \( \begin{vmatrix} x+y+2z & x & y z & y+z+2x & y z & x & z+x+2y \end{vmatrix} = k(x+y+z)^3 \), then the value of \( k \) is

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For symmetric determinants, try adding rows/columns to extract common factors like \( (x+y+z) \).
Updated On: Apr 23, 2026
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The Correct Option is B

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