Question:medium
If $\arg(z_1) = \arg(z_2)$, then
If $\arg(z_1) = \arg(z_2)$, then
Show Hint
Same argument means same direction → scalar multiple relation.
Updated On: Apr 30, 2026
- $z_2 = kz_1^{-1}, (k>0)$
- $z_2 = kz_1, (k>0)$
- $|z_2| = |z_1|$
- $z_1 = z_2$
- $|z_2| = |z_1|$
Show Solution
The Correct Option is B
Solution and Explanation
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