If an X-linked recessive disorder is in Hardy-Weinberg equilibrium and the incidence in males equals 1 in 100, then the expected incidence of affected homozygous females would be-
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For X-linked recessive traits, the female disease incidence is the square of the male disease incidence: \(\text{Female incidence} = (\text{Male incidence})^2\).
In this case, \((1/100)^2 = 1/10000\).