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If $\alpha, \beta, \gamma, \delta$ are the roots of the equation $12x^4-56x^3+89x^2-56x+12=0$ such that $\alpha\beta = \gamma\delta = 1$ and $\frac{\alpha+\beta}{\gamma+\delta}>1$, then $\frac{\alpha+\beta}{\gamma+\delta} =$

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Recognize reciprocal equations by their symmetric coefficients. The standard technique is to divide by the middle power of $x$ (here $x^2$) and use the substitution $y=x+1/x$ to reduce it to a simpler equation.

Updated On: Mar 30, 2026

$65/6$
$13/2$
$17/15$
$15/13$

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The Correct Option is D

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If $\alpha, \beta, \gamma, \delta$ are the roots of the equation $12x^4-56x^3+89x^2-56x+12=0$ such that $\alpha\beta = \gamma\delta = 1$ and $\frac{\alpha+\beta}{\gamma+\delta}>1$, then $\frac{\alpha+\beta}{\gamma+\delta} =$

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The Correct Option is D

Solution and Explanation

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