Question:medium

If $\alpha, \beta, \gamma$ are the roots of the equation $x^3 + \frac{a}{2}x + b = 0$ and $(\alpha-\beta)(\alpha-\gamma)$, $(\beta-\alpha)(\beta-\gamma)$, $(\gamma-\alpha)(\gamma-\beta)$ are the roots of the equation $(y+a)^3 + K(y+a)^2 + L = 0$, then $\frac{L}{K}= $

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For roots expressed as differences of original roots, use the derivative $P'(\alpha)$ to simplify calculations for transformed polynomials.

Updated On: Mar 30, 2026

$\frac{32b^2}{a}$
$\frac{16a^2}{b}$
$\frac{18b^2}{a}$
$\frac{12a^2}{b}$

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The Correct Option is C

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