If \(\alpha,\beta,5\) are the roots of the equation
\[
x^3-ax+a=
\frac{\sin^2x+\cos^4x}
{\cos^2x+\sin^4x},
\]
then \(a(\alpha+\beta)=\)
Show Hint
If
\[
\sin^2x+\cos^2x=1,
\]
then
\[
\boxed{
\sin^2x+\cos^4x
=
\cos^2x+\sin^4x,
}
\]
so the given trigonometric expression simplifies directly to
\[
\boxed{1.}
\]
Then apply Vieta's formulas to the resulting polynomial.