Question:medium

If a real valued function \(f:A\rightarrow B\) defined by \[ f(x)=\sin^{-1}\!\left(\sqrt{x^{2}-4x+5}\right) \] is a bijection, then \(A\cup B=\)

Show Hint

Whenever an inverse trigonometric function appears, first check whether its argument lies in the permitted interval. Most questions become simple after applying this restriction.
Updated On: Jun 22, 2026
  • \(\mathbb R\)
  • \([0,1]\cup\left[0,\frac{\pi}{2}\right]\)
  • \([-1,1]\cup\left[-\frac{\pi}{2},\frac{\pi}{2}\right]\)
  • \(\left\{2,\frac{\pi}{2}\right\}\) \bigskip
Show Solution

The Correct Option is D

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