Question:medium

If a radioactive substance decays 10% in every 16 hours, then the percentage of the radioactive substance that remains after 2 days is

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For radioactive decay problems involving fractions or percentages over time, you often don't need to calculate the decay constant $\lambda$ explicitly. Use the property $(e^{-\lambda t_1})^{t_2/t_1} = e^{-\lambda t_2}$. If a fraction $f$ remains after time $t_1$, then after time $n \cdot t_1$, the fraction remaining will be $f^n$.

Updated On: Mar 30, 2026

82.2
18.8
27.1
72.9

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The Correct Option is D

Solution and Explanation

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