Question:medium

If \[ A=\operatorname{Adj}\!\left(-2\left(\operatorname{Adj}(P^{-1})\right)\right) \] and \[ P= \begin{bmatrix} 1& 2& 1 1& 0& 1 0& 1& 2 \end{bmatrix}, \] then \(|A|=\)

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For an \(n\times n\) matrix, \[ \boxed{ |\operatorname{Adj}(A)|=|A|^{\,n-1} } \] and \[ \boxed{ |kA|=k^n|A|. } \] For a \(3\times3\) matrix, \[ |\operatorname{Adj}(A)|=|A|^2. \]
Updated On: Jul 18, 2026
  • \(-\dfrac14\)
  • \(\dfrac14\)
  • \(\dfrac34\)
  • \(\dfrac23\)
Show Solution

The Correct Option is B

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