If
\[
A=\operatorname{Adj}\!\left(-2\left(\operatorname{Adj}(P^{-1})\right)\right)
\]
and
\[
P=
\begin{bmatrix}
1& 2& 1
1& 0& 1
0& 1& 2
\end{bmatrix},
\]
then \(|A|=\)
Show Hint
For an \(n\times n\) matrix,
\[
\boxed{
|\operatorname{Adj}(A)|=|A|^{\,n-1}
}
\]
and
\[
\boxed{
|kA|=k^n|A|.
}
\]
For a \(3\times3\) matrix,
\[
|\operatorname{Adj}(A)|=|A|^2.
\]