Question:medium

If a normal drawn at the point \(t=1\) on the parabola \[ x^2+4y+2x-8=0 \] intersects the parabola again at a point \(A(\alpha,\beta)\), then \(4\alpha\beta=\)

Show Hint

For normals to a parabola, first convert the equation into standard form, use the standard normal equation in parameter form, and then substitute back into the parabola to obtain the second point of intersection.
Updated On: Jul 18, 2026
  • \(189\)
  • \(-24\)
  • \(152\)
  • \(-38\)
Show Solution

The Correct Option is A

Solution and Explanation

Was this answer helpful?
0

Top Questions on Conic sections

Questions Asked in TS EAMCET exam