Question:medium

If $A$ is a square matrix of order 3 and $|A|=5$, then the value of $|2A^{T}|$ is

Show Hint

When a constant comes out of a determinant, it is raised to the power of the matrix order.
  • -10
  • 10
  • 40
  • -40
Show Solution

The Correct Option is C

Solution and Explanation

To find the value of \(|2A^T|\), we need to understand certain properties of determinants and transposition of matrices.

  1. Property 1: Transpose of a Matrix
    • The determinant of a matrix remains unchanged when the matrix is transposed. Therefore, \(|A^T| = |A|\).
  2. Given Information
    • The determinant of the original matrix \(A\) is given as \(|A| = 5\).
  3. Transposition Impact
    • From Property 1, we have \(|A^T| = |A| = 5\).
  4. Property 2: Determinants and Scalar Multiplication
    • If a scalar \(k\) multiplies a square matrix \(A\) of order \(n\), the determinant of the resultant matrix is given by \(|kA| = k^n \cdot |A|\), where \(n\) is the order of the matrix.
    • In our case, since \(A\) is a 3x3 matrix, \(n = 3\).
  5. Calculate |2A^T|
    • Using Property 2, we have \(|2A^T| = 2^3 \cdot |A^T|\).
    • Since \(|A^T| = |A| = 5\), substituting the values gives us:

\(|2A^T| = 2^3 \cdot 5 = 8 \cdot 5 = 40\)

Thus, the value of \(|2A^T|\) is 40.

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