Question:medium

If $A = \begin{pmatrix} 1 & 5 & 2 \\ 4 & 1 & 3 \\ 2 & 6 & 3 \end{pmatrix}$, then $|(\text{Adj A})^{-1}| =$

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This problem is solved efficiently by knowing determinant properties. Direct calculation of the adjoint, its inverse, and then its determinant would be extremely time-consuming. Always look for ways to use properties like $|M^{-1}|=1/|M|$ and $|\text{Adj A}|=|A|^{n-1}$.
Updated On: Mar 30, 2026
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The Correct Option is B

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