Question:medium

If \[ A= \begin{bmatrix} 1& 2&-1\\ -1& 1& 2\\ 2&-1& 1 \end{bmatrix}, \] then \[ (Adj~A)(Adj(Adj~A)) = \]

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Remember the identity \[ Adj(Adj(A))=|A|^{n-2}A. \] For a \(3\times3\) matrix it reduces directly to \[ Adj(Adj(A))=|A|A. \]
Updated On: Jun 22, 2026
  • \(196A^2\)
  • \(14(Adj~A)\)
  • \(14A\)
  • \(\sqrt{196I}\) \bigskip
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The Correct Option is A

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