Question:medium

If \( a=|\bar{a}| \); \( b=|\bar{b}| \) then \( \left(\frac{\bar{a}}{a^2} - \frac{\bar{b}}{b^2}\right)^2 = \)

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Use \( |\vec{v}|^2 = \vec{v} \cdot \vec{v} \) to expand.

Updated On: Mar 26, 2026

\( \left(\frac{\bar{a}-\bar{b}}{a^2b^2}\right)^2 \)
\( \left(\frac{\bar{a}-\bar{b}}{ab}\right)^2 \)
\( \left(\frac{b\bar{a}-a\bar{b}}{ab}\right)^2 \)
\( \left(\frac{a\bar{a}-b\bar{b}}{a^2b^2}\right)^2 \)

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The Correct Option is B

Solution and Explanation

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