We start with the given equation:
$\sqrt{29 - 12\sqrt{5}} = a + b\sqrt{n}$
Square both sides of the equation:
$29 - 12\sqrt{5} = (a + b\sqrt{n})^2 = a^2 + 2ab\sqrt{n} + b^2n$
By comparing the rational and irrational parts of the equation, we get two separate equations:
- $a^2 + b^2n = 29$ (for the rational parts)
- $2ab\sqrt{n} = -12\sqrt{5}$ (for the irrational parts)
From the irrational part, $2ab\sqrt{n} = -12\sqrt{5}$, we can deduce that $n = 5$. Substituting this into the equation yields:
$2ab\sqrt{5} = -12\sqrt{5} \implies ab = -6$
Now, substitute $n = 5$ into the rational part equation, $a^2 + b^2n = 29$:
$a^2 + 5b^2 = 29$
We now have a system of two equations:
1. $ab = -6$
2. $a^2 + 5b^2 = 29$
Solving these equations (either by trial and error or systematically) gives us the values $a = 3$, $b = -2$, and $n = 5$.
Therefore, the sum $a + b + n = 3 + (-2) + 5 = 6$.