If \(5\pi - 6 \cos^{-1}(\sqrt{3}(2x - 1)) = 0\), then the value of \(x\) is equal to
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Remember the range of \(\cos^{-1}(x)\) is \([0, \pi]\). Since \(\frac{5\pi}{6}\) lies in this range, the equation is valid. Always look for potential sign errors when evaluating trig values in the 2nd quadrant.