If \( -5, k, -1 \) are in A.P., then the value of \( k \) is equal to:
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Another way to solve this is to ensure the common difference is equal: \( k - (-5) = -1 - k \). Solving \( k + 5 = -1 - k \) leads to \( 2k = -6 \), giving \( k = -3 \).