Question:medium

If 4-digit numbers greater than \(5,000\) are randomly formed from the digits \(0,1,3,5\), and \(7\), what is the probability of forming a number divisible by \(5 \) when (i)the digits are repeated? (ii)the repetition of digits is not allowed?

Updated On: Jan 23, 2026
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Solution and Explanation

Given:

Digits available: 0, 1, 3, 5, 7
Four–digit numbers greater than 5000 are formed.

A number is divisible by 5 if its last digit is 0 or 5.


Total possible cases

Since the number must be greater than 5000, the thousand’s digit can be:

5 or 7


(i) Digits may be repeated

Total number of outcomes:

Thousand’s digit → 2 choices (5, 7)
Hundreds digit → 5 choices
Tens digit → 5 choices
Units digit → 5 choices

Total outcomes = 2 × 5 × 5 × 5 = 250


Favourable outcomes (divisible by 5):

Units digit must be 0 or 5 → 2 choices

Thousand’s digit → 2 choices
Hundreds digit → 5 choices
Tens digit → 5 choices

Favourable outcomes = 2 × 5 × 5 × 2 = 100


Probability:

P = 100 / 250 = 2 / 5


(ii) Repetition of digits is not allowed

Total number of outcomes:

Thousand’s digit → 2 choices (5, 7)

Remaining digits for hundreds, tens, units → 4, 3, 2 choices respectively

Total outcomes = 2 × 4 × 3 × 2 = 48


Favourable outcomes (divisible by 5):

Case 1: Units digit = 0

Thousand’s digit → 2 choices
Remaining digits → choose 2 from remaining 3 digits in order

Ways = 2 × 3 × 2 = 12

Case 2: Units digit = 5

Then thousand’s digit must be 7 (since repetition is not allowed)

Remaining digits → choose 2 from remaining 3 digits in order

Ways = 1 × 3 × 2 = 6

Total favourable outcomes = 12 + 6 = 18


Probability:

P = 18 / 48 = 3 / 8


Final Answers:

(i) Probability = 2 / 5
(ii) Probability = 3 / 8

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