Question:medium
If \( 0 < x < \pi \), then \( \frac{\sin 8x + 7\sin 6x + 18\sin 4x + 12\sin 2x}{\sin 7x + 6\sin 5x + 12\sin 3x} = \)
If \( 0 < x < \pi \), then \( \frac{\sin 8x + 7\sin 6x + 18\sin 4x + 12\sin 2x}{\sin 7x + 6\sin 5x + 12\sin 3x} = \)
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When coefficients like 1, 7, 18, 12 appear, look for Pascal-like patterns or grouping strategies that allow you to factor out a common trigonometric term like $2\cos x$.
Updated On: May 6, 2026
- \( 2\sin x \)
- \( \sin x \)
- \( \sin 2x \)
- \( 2\cos x \)
- \( \cos x \)
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The Correct Option is D
Solution and Explanation
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