Question:medium

Identify the substrate 'A' in the following reaction.
\(\text{A}\rightarrow _{\text{ii)} \Delta \,}^{\text{i) Moist Ag}_2\text{O}\,}\text{CH}_3\text{CH}_2\text{N(CH}_3)_2+\text{CH}_2 = \text{CH}_2\)

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Moist Ag2O converts the quaternary ammonium halide into its hydroxide, which on heating eliminates an alkene.
Updated On: Oct 1, 2026
  • Diethyldimethylammonium halide
  • Ethyltrimethylammonium halide
  • Diethyldimethylammonium hydroxide
  • Ethyltrimethylammonium hydroxide
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The Correct Option is A

Solution and Explanation

Step 1: Reverse the elimination:
Ethene plus $\text{C}_2\text{H}_5\text{N(CH}_3)_2$ recombine to a cation with two ethyl and two methyl groups on N.

Step 2: Consider the reagent:
Moist $\text{Ag}_2\text{O}$ is added to a halide salt, precipitating silver halide and leaving the quaternary hydroxide in solution. So the starting material must be a halide.

Step 3: Conclusion:
The halide of that cation is diethyldimethylammonium halide, option (A). The ethyltrimethyl cations would give trimethylamine instead.

Final Answer:
Substrate A is diethyldimethylammonium halide, option (A). \[ \boxed{\text{Diethyldimethylammonium halide (A)}} \]
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